Archive · 10 Sep 2026
Karen Khachanov Reaches US Open Semifinals After Blockx Retires
Karen Khachanov reached the semifinals of the US Open.
His opponent, Alexander Blockx, had several injuries during the match.
Blockx had a rib problem before the match and wore support on his ankle and thigh.
He called for medical help and eventually stopped playing.
At that point, Khachanov was ahead 6-2, 7-5, 3-2.
Khachanov said he was happy to reach the semifinals but wished Blockx a quick recovery.
This is Khachanov’s first US Open semifinal since 2022.
It is also his first Grand Slam semifinal since the 2023 Australian Open.
He will next play Alexander Zverev or Botic van de Zandschulp.
Karen Khachanov advanced to the US Open semifinals when Alexander Blockx retired trailing 6-2, 7-5, 3-2.
Blockx entered the quarter-final with a rib injury and also dealt with ankle and thigh problems during the match.
The retirement came after one hour and 38 minutes at Flushing Meadows in New York.
The world No. 50 Khachanov reached his first US Open semifinal since 2022 and first Grand Slam semifinal since the 2023 Australian Open.
Khachanov will play either top seed Alexander Zverev or Botic van de Zandschulp in the semifinals.
- Who
- Karen Khachanov and Alexander Blockx; Khachanov advanced after Blockx retired.
- What
- Khachanov reached the US Open semifinals after winning the first two sets and leading 3-2 in the third.
- When
- Wednesday, during the US Open quarter-final.
- Where
- Flushing Meadows in New York.
- Why
- Blockx retired because of injuries, including a rib issue and further ankle and thigh problems.
- Match result
- Khachanov advanced while leading 6-2, 7-5, 3-2.
- Match duration
- One hour and 38 minutes.
- Khachanov ranking
- World No. 50.
- Khachanov’s previous US Open semifinal
- 2022.
- Khachanov’s previous Grand Slam semifinal
- The 2023 Australian Open.
- Blockx’s injuries
- A rib injury, a right ankle issue requiring a brace, and a wrapped thigh.
- Next opponent
- Either top seed Alexander Zverev or Botic van de Zandschulp.