Archive · 22 May 2025
Drunk Father's Actions Lead to Infant's Tragic Death
A 28-day-old baby girl in India died because her father, who was drunk, accidentally lay on top of her while she was sleeping.
The incident happened in the early morning hours.
The father had been arguing with the family.
The baby's grandmother reported the incident to the police.
The father was arrested and charged.
The baby's mother was sleeping in the bed with her daughter when the incident happened.
The police have taken the father into custody.
The baby died because of suffocation.
The father was staying at his in-laws' residence.
A 28-day-old baby girl died of suffocation in Nirmal district, India.
The father, Alakunta Shekar, was intoxicated and lay on top of the baby.
The incident occurred between 5 am and 6 am at the in-laws' residence.
The baby's grandmother filed a complaint, and the father was arrested.
The father was charged with culpable homicide not amounting to murder.
- Who
- A 28-day-old baby girl and her father, Alakunta Shekar
- What
- A baby died due to suffocation after her father laid on top of her while intoxicated.
- When
- Between 5 am and 6 am on Tuesday.
- Where
- Khanapur town, Nirmal district, India
- Why
- The father, Alakunta Shekar, was intoxicated and lay on top of the baby, causing suffocation.
- Infant's Age
- 28 days
- Location
- Khanapur, Nirmal district
- Father's Name
- Alakunta Shekar
- Cause of Death
- Intoxication, Suffocation
- Charges
- Culpable homicide
- Father's Status
- Arrested, in judicial custody