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Rutherford's Stunning Catch Dismisses Kohli In Second ODI
Virat Kohli was batting for India against West Indies.
He scored 29 runs from 19 balls.
He tried to hit a short ball toward the third-man area.
Sherfane Rutherford ran across and caught it near the boundary.
He tossed the ball up before going outside the boundary line.
Then he came back and finished the catch.
This ended Kohli's innings and gave West Indies another wicket.
India was chasing 406 runs, while Shubman Gill was still batting strongly.
Virat Kohli was dismissed for 29 off 19 balls in the second ODI against West Indies.
Sherfane Rutherford caught Kohli near the boundary after throwing the ball up to avoid stepping over the rope.
Kohli hit three fours and one six during his brief innings.
The dismissal gave West Indies their second wicket during India's 406-run chase.
India captain Shubman Gill was unbeaten on 181 from 106 balls at the time of publication.
- Who
- Virat Kohli was dismissed by Sherfane Rutherford off Shamar Joseph's bowling, during India's chase against West Indies.
- What
- Rutherford took a remarkable boundary catch to dismiss Kohli for 29.
- Where
- Guwahati.
- When
- September 30, during the second ODI.
- Why
- Kohli attempted to ramp a short delivery toward third man, but Rutherford completed the catch near the boundary.
Key facts
- Match
- India vs West Indies, second ODI
- Venue
- Guwahati
- India's target
- 406 runs
- Virat Kohli's score
- 29 runs off 19 balls
- Kohli's boundaries
- Three fours and one six
- Catcher
- Sherfane Rutherford
- Shubman Gill's score
- 181 not out from 106 balls at the time of publication









